Integrand size = 35, antiderivative size = 125 \[ \int \frac {\sec (e+f x)}{\sqrt {4-5 \sec (e+f x)} \sqrt {2+3 \sec (e+f x)}} \, dx=\frac {2 i \cot (e+f x) \operatorname {EllipticF}\left (i \text {arcsinh}\left (\frac {\sqrt {5} \sqrt {4-5 \sec (e+f x)}}{\sqrt {2+3 \sec (e+f x)}}\right ),\frac {1}{45}\right ) \sqrt {\frac {1-\sec (e+f x)}{2+3 \sec (e+f x)}} \sqrt {\frac {1+\sec (e+f x)}{2+3 \sec (e+f x)}} (2+3 \sec (e+f x))}{3 \sqrt {5} f} \]
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Time = 0.14 (sec) , antiderivative size = 125, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.029, Rules used = {4069} \[ \int \frac {\sec (e+f x)}{\sqrt {4-5 \sec (e+f x)} \sqrt {2+3 \sec (e+f x)}} \, dx=\frac {2 i \cot (e+f x) \sqrt {\frac {1-\sec (e+f x)}{3 \sec (e+f x)+2}} \sqrt {\frac {\sec (e+f x)+1}{3 \sec (e+f x)+2}} (3 \sec (e+f x)+2) \operatorname {EllipticF}\left (i \text {arcsinh}\left (\frac {\sqrt {5} \sqrt {4-5 \sec (e+f x)}}{\sqrt {3 \sec (e+f x)+2}}\right ),\frac {1}{45}\right )}{3 \sqrt {5} f} \]
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Rule 4069
Rubi steps \begin{align*} \text {integral}& = \frac {2 i \cot (e+f x) \operatorname {EllipticF}\left (i \text {arcsinh}\left (\frac {\sqrt {5} \sqrt {4-5 \sec (e+f x)}}{\sqrt {2+3 \sec (e+f x)}}\right ),\frac {1}{45}\right ) \sqrt {\frac {1-\sec (e+f x)}{2+3 \sec (e+f x)}} \sqrt {\frac {1+\sec (e+f x)}{2+3 \sec (e+f x)}} (2+3 \sec (e+f x))}{3 \sqrt {5} f} \\ \end{align*}
Time = 0.65 (sec) , antiderivative size = 176, normalized size of antiderivative = 1.41 \[ \int \frac {\sec (e+f x)}{\sqrt {4-5 \sec (e+f x)} \sqrt {2+3 \sec (e+f x)}} \, dx=-\frac {4 \sqrt {-\cot ^2\left (\frac {1}{2} (e+f x)\right )} \sqrt {-\left ((3+2 \cos (e+f x)) \csc ^2\left (\frac {1}{2} (e+f x)\right )\right )} \sqrt {-\left ((-5+4 \cos (e+f x)) \csc ^2\left (\frac {1}{2} (e+f x)\right )\right )} \csc (e+f x) \operatorname {EllipticF}\left (\arcsin \left (\sqrt {\frac {5}{22}} \sqrt {\frac {-5+4 \cos (e+f x)}{-1+\cos (e+f x)}}\right ),\frac {44}{45}\right ) \sec (e+f x) \sin ^4\left (\frac {1}{2} (e+f x)\right )}{3 \sqrt {5} f \sqrt {4-5 \sec (e+f x)} \sqrt {2+3 \sec (e+f x)}} \]
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Time = 7.36 (sec) , antiderivative size = 142, normalized size of antiderivative = 1.14
method | result | size |
default | \(-\frac {i \sqrt {2+3 \sec \left (f x +e \right )}\, \sqrt {4-5 \sec \left (f x +e \right )}\, \sqrt {-\frac {2 \left (4 \cos \left (f x +e \right )-5\right )}{\cos \left (f x +e \right )+1}}\, \sqrt {10}\, \sqrt {\frac {2 \cos \left (f x +e \right )+3}{\cos \left (f x +e \right )+1}}\, \operatorname {EllipticF}\left (3 i \left (-\cot \left (f x +e \right )+\csc \left (f x +e \right )\right ), \frac {\sqrt {5}}{15}\right ) \left (\cos \left (f x +e \right )^{2}+\cos \left (f x +e \right )\right )}{15 f \left (8 \cos \left (f x +e \right )^{2}+2 \cos \left (f x +e \right )-15\right )}\) | \(142\) |
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\[ \int \frac {\sec (e+f x)}{\sqrt {4-5 \sec (e+f x)} \sqrt {2+3 \sec (e+f x)}} \, dx=\int { \frac {\sec \left (f x + e\right )}{\sqrt {3 \, \sec \left (f x + e\right ) + 2} \sqrt {-5 \, \sec \left (f x + e\right ) + 4}} \,d x } \]
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\[ \int \frac {\sec (e+f x)}{\sqrt {4-5 \sec (e+f x)} \sqrt {2+3 \sec (e+f x)}} \, dx=\int \frac {\sec {\left (e + f x \right )}}{\sqrt {4 - 5 \sec {\left (e + f x \right )}} \sqrt {3 \sec {\left (e + f x \right )} + 2}}\, dx \]
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\[ \int \frac {\sec (e+f x)}{\sqrt {4-5 \sec (e+f x)} \sqrt {2+3 \sec (e+f x)}} \, dx=\int { \frac {\sec \left (f x + e\right )}{\sqrt {3 \, \sec \left (f x + e\right ) + 2} \sqrt {-5 \, \sec \left (f x + e\right ) + 4}} \,d x } \]
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\[ \int \frac {\sec (e+f x)}{\sqrt {4-5 \sec (e+f x)} \sqrt {2+3 \sec (e+f x)}} \, dx=\int { \frac {\sec \left (f x + e\right )}{\sqrt {3 \, \sec \left (f x + e\right ) + 2} \sqrt {-5 \, \sec \left (f x + e\right ) + 4}} \,d x } \]
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Timed out. \[ \int \frac {\sec (e+f x)}{\sqrt {4-5 \sec (e+f x)} \sqrt {2+3 \sec (e+f x)}} \, dx=\int \frac {1}{\cos \left (e+f\,x\right )\,\sqrt {\frac {3}{\cos \left (e+f\,x\right )}+2}\,\sqrt {4-\frac {5}{\cos \left (e+f\,x\right )}}} \,d x \]
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